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Question

What is the greatest number that will divide 307 and 330 leaving remainders 3 and 7 respectively?

A
19
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B
16
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C
17
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D
23
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Solution

The correct option is A (19)


The concept we use here is: Greatest number with while, when will divide a,b,c....... the remainder are r1,r2,r3 respectively
is HCF of [(ar1)(ar2)(cr3)......]


Given 1st value is 3073=304 as remainder 3

Similar way, 2nd value is 3307=323 as remainder is 7

Now, let us find HCF of 304,323 by division method:

Now H.C.F 304,323 is 19
Hence, required greatest number is19


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