What is the hybridisation of $M n O_{4}^{-}$ ?

d s p^{2}

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s p d^{2}

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s p^{3}

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None of these

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Solution

The correct option is D $s p^{3}$
The central Mn atom in $M n O_{4}^{-}$ undergoes $s p^{3}$ hybridization as it contains 4 bonding domains and zero lone pairs of electrons.

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[N i (C O)_{4}]

[N i (C N)_{4}]^{2 -}

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

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The type of hybridisation of boron in diborane is

(a) sp (b) sp²(c) sp³ (d) dsp²

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