Question

What is the hybridisation of $\left[Ni\right(CN{)}_4{]}^{2-}$?

• A. $ds{p}^2$
• B. $sp{d}^2$
• C. $s{p}^3$
• D. None of these

Answer 1

The correct option is A $ds{p}^2$

The central Mn atom in $Mn{O}_4^{-}$ undergoes $s{p}^3$ hybridization as it contains 4 bonding domains and zero lone pairs of electrons.
Ni in $\left[\underset{–}{Ni}\right(CN{)}_4{]}^{2-}$ undergoes $ds{p}^2$ hybridization which results in square planar geometry.