Question

What is the hybridization of $P{F}_5$ in solid state?

• A. $s{p}^3$
• B. $s{p}^3{d}^2$
• C. Both $\left(a\right)$ and $\left(b\right)$
• D. $s{p}^{3}d$

Answer 1

The correct option is D $s{p}^{3}d$

$P{F}_5$ have $s{p}^{3}d$ hybridisation i.e trigonal bipyramidal in gaseous state. But $P{F}_5$ does not split into ions in solid state and exists as covalent solid.
So, the correct option is $\left(d\right)$.