What is the hydronium ion concentration of juice pH 2.25?

5.6 \times 10^{- 3} M

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0.56

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0.56 \times 10^{- 3}

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5.6 \times 10^{- 14}

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Solution

The correct option is A $5.6 \times 10^{- 3} M$
$p H = 2.25$
$[H_{3} O^{+}] = 10^{- p H} = 10^{- 2.25} = 5.6 \times 10^{- 3} M$

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What is the hydronium ion concentration of juice pH 2.25?

The correct option is A 5.6×10−3MpH=2.25 [H3O+]=10−pH=10−2.25=5.6×10−3M

The correct option is A $5.6 \times 10^{- 3} M$
$p H = 2.25$
$[H_{3} O^{+}] = 10^{- p H} = 10^{- 2.25} = 5.6 \times 10^{- 3} M$