What is the increase in entropy when $11.2 L$ of $O_{2}$ are mixed with $11.2 L$ of $H_{2}$ at $S T P$ ?

0.576 J / K

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5.76 J / K

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7.56 J / K

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2.76 J / K

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Solution

The correct option is B $5.76 J / K$
Let us consider the entropy $= 2.303 n R log (\frac{V_{2}}{V_{1}})$
Putting all given values in equation,
$= 2.303 \times 1 \times 8.314 \times log (\frac{22.4}{11.2})$
Since, $n = 1$
$= 2.303 \times 1 \times 8.314 \times log \frac{1}{2}$
Implies that
$= 5.76 J K^{- 1}$

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