What is the increase in volume when the temperature of 600 ml of air increases from 27- C to 47- C under constant pressure-A- 30 mlB- 60 mlC- 80 mlD- 40 ml

The correct option is D 40 mlAccording to Charles's Law V_1/T_1 = V_2/T_2 Substituting values, we get: V_2 = (273 + 47)/(273+27)× 600 = 640 ml Difference i ...

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Standard XII

Chemistry

Internal Energy

What is the i...

Question

What is the increase in volume when the temperature of 600 ml of air increases from $27^{o} C$ to $47^{o} C$ under constant pressure?

30 ml

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60 ml

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80 ml

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40 ml

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Solution

The correct option is D 40 ml
According to Charles's Law

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Substituting values, we get:

$V_{2} = \frac{(273 + 47)}{(273 + 27)} \times 600 = 640 m l$

Difference in volume = 640 - 600 = 40 ml

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What is the increase in volume when the temperature of 600 ml of air increases from 27oC to 47oC under constant pressure?

The correct option is D 40 mlAccording to Charles's Law V1T1=V2T2 Substituting values, we get: V2=(273+47)(273+27)×600=640 ml Difference in volume = 640 - 600 = 40 ml

What is the increase in volume when the temperature of 600 ml of air increases from $27^{o} C$ to $47^{o} C$ under constant pressure?

The correct option is D 40 ml
According to Charles's Law

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Substituting values, we get:

$V_{2} = \frac{(273 + 47)}{(273 + 27)} \times 600 = 640 m l$

Difference in volume = 640 - 600 = 40 ml