What is the least number of sides a polygon can have, such that the number of diagonals is greater than the number of sides?

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Solution

The correct option is C 6
A triangle is the smallest polygon, with 3 sides. It has no diagonals. A quadrilateral has 4 sides and 2 diagonals. A pentagon, which is a 5-sided polygon, has 5 sides and 5 diagonals.

A hexagon is a polygon with 6 sides. It has 9 diagonals.

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What is the least number of sides a polygon can have, such that the number of diagonals is greater than the number of sides?

The correct option is C 6A triangle is the smallest polygon, with 3 sides. It has no diagonals. A quadrilateral has 4 sides and 2 diagonals. A pentagon, which is a 5-sided polygon, has 5 sides and 5 diagonals. A hexagon is a polygon with 6 sides. It has 9 diagonals.

The correct option is C 6
A triangle is the smallest polygon, with 3 sides. It has no diagonals. A quadrilateral has 4 sides and 2 diagonals. A pentagon, which is a 5-sided polygon, has 5 sides and 5 diagonals.

A hexagon is a polygon with 6 sides. It has 9 diagonals.