What is the magnetic moment of $[F e F_{6}]^{3 -}$ ?

2

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5.9

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7

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35

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Solution

The correct option is A $5.9$ BM
Electronic configuration of $F e$ is $[A r] 3 d^{6} 4 s^{2}$

Oxidation state of Fe in $[F e F_{6}]^{3 -}$ is $x$ .
$\Rightarrow x - 6 = - 3$
$x = + 3$

Electronic configuration of $F e^{3 +} = [A r] 3 d^{5}$

No. of unpaired electrons in $F e^{3 +} = 5$

Magnetic moment, $μ = \sqrt{n (n + 2)} = \sqrt{5 (5 + 2)}$

$= \sqrt{35} = 5.92 B M$

Hence, option B is correct.

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Similar questions

C e^{3 +}

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[F e (C N)_{6}]^{3 -}

[F e (N H_{3})_{6}]^{3 +}

[F e F_{6}]^{3 -}

\begin{matrix} Column-I & Column-II a . & C o^{3 +} & i . & \sqrt{8} B M b . & C r^{3 +} & i i . & \sqrt{35} B M c . & F e^{3 +} & i i i . & \sqrt{3} B M d . & N i^{2 +} & i v . & \sqrt{24} B M v . & \sqrt{15} B M \end{matrix}

What can be inferred from the magnetic moment values of the following complex species?

Example Magnetic Moment (BM)

K₄[Mn(CN)₆] 2.2

[Fe(H₂O)₆]²⁺ 5.3

K₂[MnCl₄] 5.9

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