Question

​What is the magnitude of electric field intensity due to a dipole of moment 2 x 10*8 Cm at a point distant 1 m from the centre of dipole,when line joining the point to the centre of dipole makes an angle 60 degree with dipole axis?

Answer 1

$$\begin{gathered} Electricfieldintensityduetoadipolemomentisgivenaswhichmakesananangleof60degreewithdipoleaxisis \\ E=\frac{1}{4\mathrm{\pi \epsilon }}\frac{p\cos \theta }{r^2} \\ followingvaluesaregiveninquestion \\ dipolemoment\left(p\right)=2\times 10^8 \\ dis\tan cer=1m,and\theta =60degree \\ nowputallthevaluesintheaboveformula,weget \\ E=\frac{1}{4\mathrm{\pi \epsilon }}\frac{2\times 10^8\cos 60}{1^2} \\ =9\times 10^9\times 10^8,becauseweknow\cos 60=\frac{1}{2},and\frac{1}{4\mathrm{\pi \epsilon }}=9\times 10^9 \\ E=9\times 10^17ans... \end{gathered}$$