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Photoelectric Effect

What is the m...

Question

What is the magnitude of electric field intensity that balances the weight of an electron.It is given that $e = 1.6 \times 10^{- 19} C$ and $m_{e} = 9.1 \times 10^{- 31} k g$ .

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Solution

For the equilibrium of electron
$m g = e E \Rightarrow E = \frac{m g}{e}$
$= \frac{9.1 \times 10^{- 31} \times 9.8}{1.6 \times 10^{- 19}} = 5.57 \times 10^{- 11} N / C$

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