What is the magnitude of gravitational force between earth & $1$ kg object on the surface of earth?

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Solution

We know gravitation force $F = \frac{G M m}{R^{2}} = \frac{6.67 \times 10^{- 11} \times 6 \times 10^{24} \times 1}{{(6.4 \times 10^{6})}^{2}} = 9.8 N$

Where $M$ = mass of the earth, $m$ = mass of the object and $R$ = radius of earth

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Similar questions

What is the magnitude of the gravitational force between the earth and 1kg object on its surface

6 \times 10^{24}

6.4 \times 10^{6}

6 \times 10^{24} k g

6.4 \times 10^{6} m

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