Question

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is $6\times {10}^{24}$ kg and radius of the earth is $6.4\times {10}^6$)

Answer 1

$F=\frac{G{M}_{e}m}{R^2}=\frac{6.67\times {10}^{-11}\times 6\times {10}^{24}\times 1}{(6.4\times {10}^6{)}^2}$

$⟹F=9.77N$