What is the major product obtained from the following reaction?
$C H_{3} C | B r H - C H_{2} - C H_{3} C H_{3} O N a - ---- \to E t_{2} O$

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Solution

The mechanism of reaction is $S N^{2}$ due to the presence of strong solvent $E t_{2} O$ .
Here the methyl group will substitute $- B r$ group and inversion of the configuration takes place.

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