Question

What is the mass of $6.022\times {10}^{23}$ formula units of ${\left({NH}_4\right)}_2{SO}_4$?

• A. $234.11g$
  
• B. $132.11g$
  
• C. $210.29g$
  
• D. $342.14g$

Answer 1

Answer: (B)

$132.11g$

$1mole$ of $(N{H}_4{)}_{2}S{O}_4$ has $6.023\times {10}^{23}$ formula units.

So, the mass of $6.023\times {10}^{23}$ formula units of $(N{H}_4{)}_{2}S{O}_4$. is molar mass of $(N{H}_4{)}_{2}S{O}_4$

Molar mass of $(N{H}_4{)}_{2}S{O}_4$ $=2(14+4)+32+4\times 16=132g$