What is the mass of a photon of sodium light with a wavelength of $5890 ˚ A$ ?
$(h = 6.63 \times 10^{- 27} e r g - s e c, c = 3 \times 10^{10} c m / s e c)$ .

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Solution

$λ = \frac{h}{m c}$
or $m = \frac{h}{λ c}$
So, $m = \frac{6.63 \times 10^{- 27}}{5890 \times 10^{- 8} \times 3 \times 10^{10}}$
$= 3.752 \times 10^{- 33} g$ .

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