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Question

What is the maximum number of stereoisomers that could exist for the compound below?
832184_44de4244e6fe443cb4e22bed5bfc6547.png

A
6
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B
8
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C
10
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D
16
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Solution

The correct option is D 16
The number of stereoisomers can be calculated from the number of chiral centres (n), 2n.
Here number of chiral centers = 4 => 24 = 16 stereoisomers.

1126378_832184_ans_e4fc88aabeb94c4882cdc936e0f2cb38.png

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