Question

What is the maximum value of $\frac{1}{\sec \theta },$ if $0^{\circ }\le \theta \le {90}^{\circ }?$

Answer 1

$\frac{1}{sec{\theta }^{\prime }}(0^{\circ }\le \theta \le {90}^{\circ })$ (Given)

$sec\theta$ is in the denominator

The min. value of sec q will return max. value for $1/sec\theta$

But the min. value of sec q is sec $0^{\circ }=1$

Hence, the max. value of $1/sec{0}^{\circ }=1/1=1$