What is the median class for the following data given below?
Distance(km)
$1 - 11$
$11 - 21$
$21 - 31$
$31 - 41$
$41 - 51$
Number of persons
$4$
$6$
$10$
$12$
$18$

1 - 11

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11 - 21

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21 - 31

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31 - 41

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Solution

The correct option is D $31 - 41$
To find the median class:
First add the total number of frequencies.
Here, $f = 50$
$= \frac{t o t a l n u m b e r o f f r e q u e n c y}{2}$
$= \frac{(50)}{2} = 25$
Hence, the value 25 lies in the class interval 31-41 from the cummulative frequency table.

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Similar questions

Q. Calculate the mode for the following data

:

Distance(km)	$11$	$21$	$31$	$41$	$51$
Number of persons	$4$	$6$	$10$	$20$	$18$

1 \frac{1}{3} + 2 \frac{1}{4} + 3 \frac{1}{6} + 4 \frac{1}{12} + . . . + 19 \frac{2}{3}

is equal to

Q. Simplify:

\frac{4 \frac{1}{7} - 2 \frac{1}{4}}{3 \frac{1}{2} + 1 \frac{1}{7}} \div \frac{1}{2 + \frac{1}{2 + \frac{1}{5 - \frac{1}{5}}}}

Draw a frequency polygon for the following frequency distribution:
$\begin{matrix} Class interval & 1 - 10 & 11 - 20 & 21 - 30 & 31 - 40 & 41 - 50 & 51 - 60 Frequency & 8 & 3 & 6 & 12 & 2 & 7 \end{matrix}$

Q. Find the mean of the following data

Marks	1 - 10	11 - 20	21 30	31 - 40	41 -50	51 - 60	61 - 70
No. of student	6	5	8	15	7	6	3

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Distance(km)	$1 - 11$	$11 - 21$	$21 - 31$	$31 - 41$	$41 - 51$
Number of persons	$4$	$6$	$10$	$12$	$18$

What is the median class for the following data given below?Distance(km)1−1111−2121−3131−4141−51Number of persons46101218

The correct option is D 31−41To find the median class:First add the total number of frequencies.Here, f=50=totalnumberoffrequency2 =(50)2=25Hence, the value 25 lies in the class interval 31-41 from the cummulative frequency table.

What is the median class for the following data given below?
Distance(km)
$1 - 11$
$11 - 21$
$21 - 31$
$31 - 41$
$41 - 51$
Number of persons
$4$
$6$
$10$
$12$
$18$

The correct option is D $31 - 41$
To find the median class:
First add the total number of frequencies.
Here, $f = 50$
$= \frac{t o t a l n u m b e r o f f r e q u e n c y}{2}$
$= \frac{(50)}{2} = 25$
Hence, the value 25 lies in the class interval 31-41 from the cummulative frequency table.