What is the median of the numbers 4-6- 0- 9-3- -4-8- 7-6- 2-3- 12-7- 3-5- 8-2- 6-1- 3-9- 5-2-

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Standard X

Mathematics

Median

What is the m...

Question

What is the median of the numbers
$4 \cdot 6, 0, 9 \cdot 3, - 4 \cdot 8, 7 \cdot 6, 2 \cdot 3, 12 \cdot 7, 3 \cdot 5, 8 \cdot 2, 6 \cdot 1, 3 \cdot 9, 5 \cdot 2$ ?

3 \cdot 8

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4 \cdot 9

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5 \cdot 7

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6 \cdot 0

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Solution

The correct option is B $4 \cdot 9$
Arranging the given $12$ numbers in ascending order we get $- 4.8, 0, 2.3, 3.5, 3.9, 4.6, 5.2, 6.1, 7.6, 8.2, 9.3, 12.7$

In the above sequence the sixth and seventh terms are $4.6$ and $5.2$

Therefore median $= \frac{4.6 + 5.2}{2} = \frac{9.8}{2} = 4.9$

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Similar questions

$Name the multiplication property of rational numbers shown below: (i) \frac{3}{5} \times \frac{- 8}{9} = \frac{- 8}{9} \times \frac{3}{5} (i i) \frac{- 3}{4} \times (\frac{5}{7} \times \frac{- 8}{15}) = (\frac{- 3}{5} \times \frac{5}{7}) \times \frac{- 8}{15} (i i i) \frac{4}{5} \times (\frac{3}{- 8} + \frac{- 4}{7}) = \frac{4}{5} \times \frac{3}{- 8} + \frac{4}{5} \times \frac{- 4}{7} (i v) \frac{- 7}{5} \times \frac{5}{- 7} = 1 (v) \frac{8}{- 9} \times 1 = 1 \times \frac{8}{- 9} = \frac{8}{- 9} (v i) \frac{- 3}{4} \times 0 = 0$

Q. The following data gives the marks of 20 students in Mathematics (X) and statistics (Y), each out of 10, expressed as (x, y). Construct an ungrouped frequency distribution, considering single numbers as a class:

(2, 7), (3, 8), (4, 9), (2, 8), (5, 6), (5, 7), (4, 9), (3, 8), (4, 8), (2, 9), (3, 8), (4, 8), (5, 6), (4, 7),

(4, 7), (4, 6), (5, 6), (5, 7), (4, 6), (5, 5).

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Q. In the following number sequence how many odd numbers are there that are immediately preceded by an odd number and immediately followed by an even number?
7 8 6 5 2 4 3 1 8 7 9 4 6 8 3 1 4 2 7 5 6 4 8 1 3 8 9 7 2 6 4 8 3 6 5 2

Q. Study the following number line and answer the questions that follow.
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What is the median of the numbers4⋅6,0,9⋅3,−4⋅8,7⋅6,2⋅3,12⋅7,3⋅5,8⋅2,6⋅1,3⋅9,5⋅2?

The correct option is B 4⋅9Arranging the given 12 numbers in ascending order we get −4.8,0,2.3,3.5,3.9,4.6,5.2,6.1,7.6,8.2,9.3,12.7In the above sequence the sixth and seventh terms are 4.6 and 5.2Therefore median =4.6+5.22=9.82=4.9

What is the median of the numbers
$4 \cdot 6, 0, 9 \cdot 3, - 4 \cdot 8, 7 \cdot 6, 2 \cdot 3, 12 \cdot 7, 3 \cdot 5, 8 \cdot 2, 6 \cdot 1, 3 \cdot 9, 5 \cdot 2$ ?

The correct option is B $4 \cdot 9$
Arranging the given $12$ numbers in ascending order we get $- 4.8, 0, 2.3, 3.5, 3.9, 4.6, 5.2, 6.1, 7.6, 8.2, 9.3, 12.7$

In the above sequence the sixth and seventh terms are $4.6$ and $5.2$

Therefore median $= \frac{4.6 + 5.2}{2} = \frac{9.8}{2} = 4.9$