Question

What is the minimum number of identical square tiles required to cover a floor of dimension 3.78 m and 4.8 m?

• A. 2520
• B. 3780
• C. 5040
• D. 6480

Answer 1

The correct option is C 5040

For minimum tiles, the sides of the tiles should be the HCF of 3.78 m and 4.8 m
HCF of 3.78 and 4.8 = 0.06 m
Hence, number of tiles $\frac{Areaoffloor}{Areaoftile}=\frac{3.78\times 4.8}{0.06\times 0.06}=5040$