Question

What is the minimum possible force between two charges separated by a distance of 1amstrong unit

Answer 1

$$\begin{gathered} F=\frac{K{q}_1{q}_2}{r^2} \\ K=9\times {10}^9 \\ r=1A^0={10}^{-10}m \\ Sotheforcewillbeminimumwhenthecharges{q}_{1}and{q}_{2}areminimum \\ Byquantisationofcharges\left(q=n.e\right),q_{1}and{q}_{2}areintegralmultipleoftheelctronicchargee. \\ Sominimumvalueof{q}_1=q_2=e=1.602-\times {10}^{-19} \\ F=\frac{K{e}^2}{r^2}=\frac{9\times {10}^9\times {\left(1.602-\times {10}^{-19}\right)}^2}{{\left({10}^{-10}\right)}^2}=2.3098\times {10}^{-8}N \end{gathered}$$