What is the molality of a solution containing $200 m g$ of urea (molar mass $60 g {m o l}^{- 1}$ ) dissolved in $40 g$ of water?

0.0833

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0.825

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0.498

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0.0013

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Solution

The correct option is C $0.0833$
Mass of solvent= $200 m g$

Molar mass= $60 g {m o l}^{- 1}$

Mass of solvent= $40 g$ of water

Molality $(m) = \frac{m a s s o f s o l v e n t \times 1000}{m o l e c u l a r w e i g h t o f s o l u t e \times m a s s o f s o l v e n t}$

$= \frac{200 \times 10^{- 3} \times 1000}{60 \times 40} = 0.0833$

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g m o l^{- 1}

120 g

60 g {m o l}^{- 1}

1000 g

1.15 g / m l

m o l^{- 1})

c m^{3}

(k_{b})

15 g

= 60 g {m o l}^{- 1}

= 190 g {m o l}^{- 1}

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