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Question

What is the molarity of a 4.9% H3PO4 solution by mass? (Density of H3PO4 solution = 1.22 g/mL)?

A
0.61 M
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B
0.05 M
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C
1.22 M
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D
1.54 M
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Solution

The correct option is A 0.61 M
Let the mass of the solution be 100 g.
So, 4.9 g of H3PO4 is present in 100 g of solution.
Moles of H3PO4
given massmolar mass=4.998=0.05 moles

Density=mass of solutionvolume of solution

⇒ volume of H3PO4=1001.22=81.97 mL
Molarity=moles of solute of H3PO4total volume of solution in mL×1000
Molarity = 0.0581.97×1000=0.61 M

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