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Question

What is the molarity of H2SO4 solution that has a density of 1.84 g cc−1 and contains 98% by mass of H2SO4? (Given atomic mass of S = 32 amu)

A
4.18 M
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B
8.14 M
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C
18.4 M
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D
18 M
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Solution

The correct option is C 18.4 M
Given:
Mass% = 98% i.e. 98 g of H2SO4 is present in 100 g of the solution.
Density =1.84 g cc1=1.84 g mL1

Hence, volume =1001.84 mL=118.4 L
Given mass of H2SO4=98 g
Number of moles of H2SO4=9898=1

Molarity=molesvolume of the solution in L

Molarity=11/18.4=18.4 M

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