What is the number in place of $^{'} ?^{'}$ ?
$6, 15, 35, ? -, 143, 221$

45

No worries! We‘ve got your back. Try BYJU‘S free classes today!

65

No worries! We‘ve got your back. Try BYJU‘S free classes today!

77

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

93

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $77$
$2 \times 3 = 6$
$3 \times 5 = 15$
$5 \times 7 = 35$
$7 \times 11 = 77$
$11 \times 13 = 143$
$13 \times 17 = 221$
Thus $77$ is correct.
Hence, Option C is correct answer.

Suggest Corrections

Similar questions

We have marks of different students in three different tables below, which one of the following is the easiest to analyse?
A)

$\begin{matrix} S t u d e n t & M a r k s s c o r e d (O u t o f 100) A & 77 B & 65 C & 93 D & 42 E & 88 \end{matrix}$

$\begin{matrix} S t u d e n t & M a r k s s c o r e d (O u t o f 100) E & 88 D & 42 C & 93 B & 65 A & 77 \end{matrix}$

$\begin{matrix} S t u d e n t & M a r k s s c o r e d (O u t o f 100) D & 42 B & 65 A & 77 E & 88 C & 93 \end{matrix}$

Q. If

\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{2^{5} + 2^{5}} \times \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{3^{5} + 3^{5} + 3^{5}} = 8^{n}

, then n is:

Let N = $\frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} \cdot \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}$ then the value of ${log}_{2} N$ =

Q. Let

N = \frac{4^{5} + 4^{5} + 4^{5} + 4^{5}}{3^{5} + 3^{5} + 3^{5}} . \frac{6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5} + 6^{5}}{2^{5} + 2^{5}}

, then the value of

{log}_{2} N =

Q. 77, 68 , 56

The number with more beads in the tens place is .

Join BYJU'S Learning Program

What is the number in place of ′?′?6,15,35,?–,143,221

The correct option is B 772×3=63×5=155×7=357×11=7711×13=14313×17=221Thus 77 is correct.Hence, Option C is correct answer.

What is the number in place of $^{'} ?^{'}$ ?
$6, 15, 35, ? -, 143, 221$

The correct option is B $77$
$2 \times 3 = 6$
$3 \times 5 = 15$
$5 \times 7 = 35$
$7 \times 11 = 77$
$11 \times 13 = 143$
$13 \times 17 = 221$
Thus $77$ is correct.
Hence, Option C is correct answer.