Question

what is the number of atoms present in 48 g of sulphur

Answer 1

Hi,
Molar mass of S₈ = 256.52 g/mol
Number of molecules present in 256.52 g = 6.022 X10²³ molecules

Number of molecules present in 48 g = $\frac{{\text{6.022 X 10}}^{23}}{256.52}X48$ = 1.1268 X 10²³ molecules6.022×1023256.52×

Since 1 molecule of S₈ has 8 sulphur atoms, so number of sulphur atoms in 1.12​68 X 10²³ molecules is gives
1.12​68 X 10²³ X 8 = 9.014 X 10²³ atoms

Regards