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Limiting Reagent or Reactant

What is the n...

Question

What is the number of moles of $F e ({O H}_{3})$ that can be produced by allowing $1$ mole of ${F e}_{2} S_{3}$ , $2$ moles of $H_{2} O$ and $3$ moles of $O_{2}$ to react? (as nearest integer)
$2 {F e}_{2} S_{3} + 6 H_{2} O + 3 O_{2} \to 4 F e (O H)_{3} + 6 S$

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Solution

$2 {F e}_{2} S_{3} + 6 H_{2} O + 3 O_{2} \to 4 F e {O H}_{3} + 6 S$
$2$ $6$ $3$ $4$ (From stoichiometry)
$1$ $2$ $3$ $?$ (Given)
So, $H_{2} O$ is limiting reagent here.
$F e (O H)_{3}$ produces $= 4 \times \frac{2}{6} = 1.34$ moles
So, nearest integer is $1$ .

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