Question

What is the number of moles of $KMn{O}_4$ that will be needed to react completely with one mole of ferrous oxalate in an acidic medium?

Answer 1

The balanced chemical reaction can be given as :

${3MnO}_4^{-}+5Fe{C}_2{O}_4^{2-}+2{4H}^{+}\to {3Mn}^{+2}+5{Fe}^{3+}+10{CO}_2+12H_{2}O$

Therefore, as per stiochiometry,

3 moles of ${KMnO}_4$ are needed to react completely with 5 moles of ferrous oxalate.

$\therefore$ For one mole of Ferrous oxalate $=\frac{3}{5}$ moles of ${KMnO}_4$ are required.

$\therefore$ For one mole of ferrous oxalate in acidic medium, $\frac{3}{5}$ moles of ${KMnO}_4$ are needed.