Question

What is the output printed by the following C code?
# include < stdio.h>
int main ( )
{
char a[6] = " world";
int i, j;
for ( i = 0, j = 5; i < j; a[i++] = a[ j - - ]);
printf ("%s\n", a);
}

• A. worow
• B. dlrow
• C. Null string
• D. dlrld

Answer 1

The correct option is C Null string

char a[6] =

w	o	r	l	d	\0
a[0]	1	2	3	4	5

When Loop will execute first time,
a[0] = a[5]
a[0] = '\0'
printf ("%s", a), the string starting at address a prints the string starting with '/0' and it indicates the end of string, so it will print null string.