Question

What is the oxidation no of $S$ in $H_2{S}_2{O}_8$?

• A. 6
• B. 7
• C. 4
• D. 2

Answer 1

Answer: (A)

6

In this, there is $one$ $peroxy$ $bond.$ the oxidation number is $-1$, where there is a $peroxy$ $linkage.$

For remaining $0$ atoms, it is $-2.$

For ${}^{\prime }{6}^{\prime }$.${}^{\prime }{0}^{\prime }$ atoms $⟶-2$, remaining $2⟶-1$

So, in $H_2{S}_2{O}_8,$

$H⟶+1$, Let $x$ be the oxidation state of $S$.

$2\left(1\right)+2\left(x\right)+6(-2)+2(-1{)}_{=}02+2x-14=0,2x=12x=6$