What is the oxidation number of $F e$ in $[F e (H_{2} O)_{5} (N O)]^{2 +}$ ion?

+ 2

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+ 3

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+ 1

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0

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Solution

The correct option is A $+ 1$
Let X be the oxidation number of iron in $[F e (H_{2} O)_{5} (N O)]^{2 +}$ .
$X + 5 (0) + (+ 1) = + 2 o r X = + 1$ .

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