What is the oxidation number of sulphur in ${N a}_{2} S_{4} O_{6}$ ?

2 / 3

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3 / 2

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3 / 5

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5 / 2

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Solution

The correct option is D $5 / 2$
oxidation number of sulphur in ${N a}_{2} S_{4} O_{6}$ is
$2 + 4 x - 2 * 6 = 0 x = 5 / 2$

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What is the oxidation number of sulphur in Na2S4O6?

The correct option is D 5/2oxidation number of sulphur in Na2S4O6 is2+4x−2∗6=0x=5/2

What is the oxidation number of sulphur in ${N a}_{2} S_{4} O_{6}$ ?

The correct option is D $5 / 2$
oxidation number of sulphur in ${N a}_{2} S_{4} O_{6}$ is
$2 + 4 x - 2 * 6 = 0 x = 5 / 2$