What is the oxidation number of underlined element?

$C {S - -}_{2}$

Open in App

Solution

Let the oxidation number of S in $C {S - -}_{2}$ be $x$ .
Since the overall charge on the compound is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
Therefore, $4 + 2 (x) = 0$
or, $x = - 2$
Hence, the oxidation number of S in $C {S - -}_{2}$ is $- 2$ .

Suggest Corrections

Similar questions

{S - -}^{2 -}

K_{2} F e - - - O_{4}

{S - -}_{2} O_{8}^{2 -}

[N i - - - (C O)_{4}]

{M g - -- -}_{3} N_{2}

Join BYJU'S Learning Program