What is the oxidation number of underlined element?

$K C l - - - O_{3}$

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Solution

Let $x$ be the oxidation number of Cl in $K C - - l O_{3}$ .
Since the overall charge on the compound is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
Therefore, $+ 1 + x + 3 (- 2) = 0$
Hence, $x = + 5$
Hence, the oxidation number of Cl in $K C l - - - O_{3}$ is $+ 5$ .

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