What is the oxidation state of nitrogen in $N_{2} O_{5}$ ?

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Solution

The correct option is A 5
Let the oxidation state of $N$ be $x$ . Oxidation state of $O$ is $- 2$ as it is in oxide form.

$\Rightarrow 2 x + 5 (- 2) = 0$
$\Rightarrow x = \frac{10}{2} = + 5$

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