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VSEPR Theory

What is the o...

Question

What is the oxidation state of sulphur in the following:
a) $S F_{6}$ b) ${N a}_{2} S_{2} O_{3}$

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Solution

$a)$ We know Oxidation state of $F$ is $- 1$
$x + (- 1) 6 = 0$
$⟹ x - 6 = 0$
$⟹ x = + 6$
$b)$ We know $N a$ is $+ 1$ and $O$ is $- 2$
So, $2 (+ 1) + 2 x + 3 (- 2) = 0$
$⟹ 2 + 2 x - 6 = 0$
$⟹ 2 x = 4$
$⟹ x = + 2$
Here, oxidation state is $+ 2$

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