What is the oxidation state of sulphur in the following: a) SF6 b) Na2S2O3
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Solution
a) We know Oxidation state of F is −1 x+(−1)6=0 ⟹x−6=0 ⟹x=+6 b) We know Na is +1 and O is −2 So, 2(+1)+2x+3(−2)=0 ⟹2+2x−6=0 ⟹2x=4 ⟹x=+2 Here, oxidation state is +2