What is the oxidation state of Xe in $X e [P t F_{6}]$ ?

+ 1

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Solution

The correct option is A + 2
The species $[P t F_{6}]$ has a charge of $- 2$ because F has charge -1 and Pt has charge +4. Let the oxidation state of Xe = x.
$x + 4 + 6 (- 1) = 0$
$⟹ x = + 2$
Hence, in $X e P t F_{6}$ , $X e$ has an oxidation number of $+ 2$ .

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