What is the oxidizing agent in the following redox reaction- Zn s - Cu 2- aq - Zn 2- aq - Cu s A- Cu 2-B- Zn 2-C- ZnD- Cu

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Oxidation and Reduction

What is the o...

Question

What is the oxidizing agent in the following redox reaction?

$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$

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Zn²⁺

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Cu²⁺

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Solution

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The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

E^{\circ}

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

25^{\circ} C

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +} (a q)

E^{\circ}

{Zn(s)|Zn}^{2 +} (aq) | | {Cu}^{2 +} (aq)|Cu(s)

1.10

25^{\circ} C

Zn(s) + {Cu}^{2 +} (aq) \to Cu(s) + {Zn}^{2 +} (aq)

1.94 \times 10^{x}

x

E^{\circ}

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u is 1.10 V at 25^{\circ} C

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +}

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