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Balancing Redox Equations

What is the p...

Question

What is the percent yield of the following reaction if $50 g$ of $C a C O_{3}$ is heated to give $15 g$ of CaO?
$C a C O_{3} \to C a O + C O_{2}$

44.6 %

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50.0 %

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66.6 %

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53.5 %

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Solution

The correct option is D $53.5 %$
For the given reaction,
$C a C O_{3} \to C a O + C O_{2}$
As per stoichiometry, $1$ mol of $C a C O_{3}$ decomposes to give $1$ mol of $C a O$ and $1$ mol of $C O_{2}$
Initial moles of $C a C O_{3} = \frac{50}{100} = 0.5 mol$
So, theoretically,
moles of $C a O$ produced $= 0.5 mol$
$∴$ Mass produced $= 0.5 \times molar mass of C a O = 0.5 \times 56 = 28 g$
But actual yield is $15 g$ of $C a O$
So, $P e r c e n t a g e y i e l d = \frac{A c t u a l y i e l d}{T h e o r e t i c a l y i e l d} \times 100$
$= \frac{15 g}{28 g} \times 100 ≃ 53.5 %$

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