Question

What is the percentage composition of Na2S2O35H2O

Answer 1

Dear stduent ,

Molecular mass of Na₂S₂O₃.5H₂O = 2$\times$23 + 2$\times$32+ 3$\times$16 + 5$\times$18 = 248 g
Percentage composition of sodium = (46/248)$\times$100 = 18.54%
Sulphur = (64/248)$\times$100 = 25.80%
Oxygen =(128/248)$\times$100 = 51.61%
Hydrogen = 4.03%

Regards