Question

What is the perimeter of the triangle ABC in the given figure ABCD? ( Take $\sqrt{2}$ = 1.4 )

• A. 3.7 m
• B. 3.8 m
• C. 4.7 m
• D. 4.8 m

Answer 1

The correct option is D

4.8 m

ABC is a right - angled isosceles triangle.
The sides are in the ratio 1 : 1 : $\sqrt{2}$

Let the sides be x, x , $\sqrt{2}$ x
Here, x $=\sqrt{2}$
$\therefore$ The Length of AC $=\sqrt{2}$x
$=\sqrt{2}\times \sqrt{2}=$ 2 m

$\therefore$ Perimeter of the figure ABC = AB + BC + AC

$=\sqrt{2}+\sqrt{2}+2=1.4+1.4+2=4.8\text{m}$