1
Question
What is the pH of 10−7mol L−1 HCl solution at 25∘C?
What is the pH of 10−7mol L−1 HCl solution at 25∘C?
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Solution
The correct option is C 6.7
For 10−7mol L−1HCl, the concentration of H+ due to the dissociation of water will not be negligible in comparison to the concentration H+ from the acid. Hence, we have
[H+]total = [H+]acid + [H+]water
=10−7+10−7 Since[H+] in water is10−7 mol L−1 at25∘C
=10−7(1+1)
=2×10−7
pH=−log[H+]=−log[2×10−7]
pH = 6.7
6.7
For 10−7mol L−1HCl, the concentration of H+ due to the dissociation of water will not be negligible in comparison to the concentration H+ from the acid. Hence, we have
[H+]total = [H+]acid + [H+]water
=10−7+10−7 Since[H+] in water is10−7 mol L−1 at25∘C
=10−7(1+1)
=2×10−7
pH=−log[H+]=−log[2×10−7]
pH = 6.7
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