Question

What is the phase difference between the two simple harmonic motions whose displacement – time graphs are shown in fig ?

• A. Zero
• B. $\pi /4$
• C. $\pi /2$
• D. $\pi$

Answer 1

The correct option is C $\pi /2$

The phase constant of motions I is zero whereas that of motion II is $\pi /2$ (sinceits displacement is negative maximum at time t = 0). Therefore, the phase difference between the two motions in is $\pi /2$ . Hence the correct choice is (c).