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Standard XII

Physics

Power and Thin Lenses in Contact

What is the p...

Question

What is the position and nature of image formed by lens combination shown in figure?
$(f_{1}, f_{2}$ are focal length $)$

70

cm from point

B

at left; virtual

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40

cm from point

B

at right ;real

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\frac{20}{3}

cm from point

B

at right ,real

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70

cm from point

B

at right ,real

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Solution

The correct option is C $70$ cm from point $B$ at right ,real
For first lens
$\frac{1}{V} - \frac{1}{- 20} = \frac{1}{5}$
$V = \frac{20}{3}$
For second lens
$V = \frac{20}{3} - 2 = \frac{14}{3}$
$\frac{1}{V} - \frac{1}{\frac{14}{3}} = \frac{1}{- 5}$
$V = 70 c m$

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What is the position and nature of image formed by lens combination shown in figure? (f1,f2 are focal length )

The correct option is C 70cm from point B at right ,realFor first lens1V−1−20=15V=203For second lensV=203−2=1431V−1143=1−5V=70cm

What is the position and nature of image formed by lens combination shown in figure?
$(f_{1}, f_{2}$ are focal length $)$

The correct option is C $70$ cm from point $B$ at right ,real
For first lens
$\frac{1}{V} - \frac{1}{- 20} = \frac{1}{5}$
$V = \frac{20}{3}$
For second lens
$V = \frac{20}{3} - 2 = \frac{14}{3}$
$\frac{1}{V} - \frac{1}{\frac{14}{3}} = \frac{1}{- 5}$
$V = 70 c m$