What is the position of an image, when an object is placed at a distance of 10cm in front of the concave mirror? The image is virtual and double in size as compared to the object

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Solution

Given,
Object distance, $u = 10 c m$

Magnification, $m = 2$

We know,

$m = - \frac{v}{m}$

$2 = \frac{- v}{- 10}$

$v = 20 c m$

Image will be formed on the opposite side as that of object

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What is the position of an image, when an object is placed at a distance of 10cm in front of the concave mirror? The image is virtual and double in size as compared to the object

Given,Object distance, u=10cmMagnification, m=2We know,m=−vm2=−v−10v=20cmImage will be formed on the opposite side as that of object

Given,
Object distance, $u = 10 c m$

Magnification, $m = 2$

We know,

$m = - \frac{v}{m}$

$2 = \frac{- v}{- 10}$

$v = 20 c m$

Image will be formed on the opposite side as that of object