What is the potential difference between the terminals of a battery if $250 J$ of work is required to transfer $20 C$ of charge from one terminal of the battery to the other?

10.5 V

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12.5 V

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15.5 V

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17.5 V

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Solution

The correct option is B $12.5 V$
Given:
$w = 250 J$
$q = 20 C$

So, the potential difference between the terminals of the battery is,

$Δ V = \frac{w}{q}$

$\Rightarrow Δ V = \frac{250}{20} = 12.5 V$

Hence, option $(B)$ is the correct answer.

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Similar questions

(a) What do you understand by the term "potential difference"?
(b) What is meant by saying that the potential difference between two points is 1 volt?
(c) What is the potential difference between the terminals of a battery if 250 joules of work is required to transfer 20 coulombs of charge from one terminal of battery to the other?
(d) What is a voltmeter ? How is a voltmeter connected in the circuit to measure the potential difference between two points. Explain with the help of a diagram.
(e) State- whether a voltmeter has a high resistance or a low resistance. Give reason for your answer.

If 300 joules of work is required to transfer 30 coulombs of charge, then the potential difference between two ends of battery is

For a real battery the work done by battery is equal to increase in electrical potential energy of a positive charge as charge moves from negative terminal to positive terminal of battery

Is this above statement true. ??

Q. A parallel plate capacitor of capacitance

C

is connected to a battery and is charge to a potential difference

V

. Another capacitor of capacitor

2 C

2 V

. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is:

Q. A parallel plate capacitor of capacitance

C

is connected to a battery and is charged to a potential difference

V

.
Another capacitor of capacitance

2 C

is connected to another battery and is charged to potential difference

2 V

. The charging batteries are now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

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What is the potential difference between the terminals of a battery if 250 J of work is required to transfer 20 C of charge from one terminal of the battery to the other?

The correct option is B 12.5 VGiven: w=250 J q=20 C So, the potential difference between the terminals of the battery is, ΔV=wq ⇒ΔV=25020=12.5 V Hence, option (B) is the correct answer.

What is the potential difference between the terminals of a battery if $250 J$ of work is required to transfer $20 C$ of charge from one terminal of the battery to the other?

The correct option is B $12.5 V$
Given:
$w = 250 J$
$q = 20 C$

So, the potential difference between the terminals of the battery is,

$Δ V = \frac{w}{q}$

$\Rightarrow Δ V = \frac{250}{20} = 12.5 V$

Hence, option $(B)$ is the correct answer.