What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature? Surface tension of mercury at that temperature (20°C) is 4.65 × 10^–1 N m^–1. The atmospheric pressure is 1.01 × 10⁵ Pa. Also give the excess pressure inside the drop.

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Solution

Answer:

Radius of the mercury drop, r = 3.00 mm = 3 × 10^–3 m

Surface tension of mercury, S = 4.65 × 10^–1 N m^–1

Atmospheric pressure, P₀ = 1.01 × 10⁵ Pa

Total pressure inside the mercury drop

= Excess pressure inside mercury + Atmospheric pressure

= 1.0131 × 10⁵

= 1.01 ×10⁵ Pa

Excess pressure

= 310 Pa

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What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature? Surface tension of mercury at that temperature (20°C) is 4.65 × 10–1 N m–1. The atmospheric pressure is 1.01 × 105 Pa. Also give the excess pressure inside the drop.

What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature? Surface tension of mercury at that temperature (20°C) is 4.65 × 10^–1 N m^–1. The atmospheric pressure is 1.01 × 10⁵ Pa. Also give the excess pressure inside the drop.