What is the pressure of the water column whose height=10CM density=20kg gravity=9.8

Open in App

Solution

pressure equation p = ρgh

ρ ( density ) = 20 kg

h ( height ) = 10cm = 0.1 m

g (gravity ) = 9.8 m/s^2

p = 20 x 0.1 x 9.8 = 19.6 atm

Suggest Corrections

Similar questions

Q. The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units using the following data : Specific gravity of mercury = 13.6, Density of water

= 10^{3} k g / m^{3}, g = 9.8 m / s^{2}

at Calcutta

. P r e s s u r e = h p g

in usual symbols.

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units using the following data : Specific gravity of mercuty = 13.6, Density of water = $10^{3} k g / m^{3}$ , g = $9.8 m / s^{2}$ at Calcutta. Pressure = hpg in usual symbols.

It is given that both liquid A and liquid B exert the same amount of pressure. The density of liquid A is twice the density of liquid B. The height of the column of liquid B is 10 cm. Then what would be the height of the column of liquid A?(Use the formula for Pressure(P) as P = $ρ g h$ ; $^{'} ρ^{'}$ is the density of the liquid, 'g' -acceleration due to gravity, 'h'- height of the liquid column)

The height of a mercury column in a barometer in a Calcutta library was recorded to be 75cm.Calculate this pressure in SI and CGS units using the following data : Specific gravity of mercury = 13.6,Density of water = 10³kg/m³,g = 9.8 m/s² at Calcutta .Pressure = hpg in usual symbols.

Q. It is given that both liquid A and liquid B exert the same amount of pressure on their respective bases. The density of liquid A is twice the density of liquid B. The height of the column of liquid B is

10 c m

. What would be the height of the column of liquid A?

Join BYJU'S Learning Program

What is the pressure of the water column whose height=10CM density=20kg gravity=9.8

pressure equation p = ρgh ρ ( density ) = 20 kg h ( height ) = 10cm = 0.1 m g (gravity ) = 9.8 m/s^2 p = 20 x 0.1 x 9.8 = 19.6 atm

pressure equation p = ρgh

ρ ( density ) = 20 kg

h ( height ) = 10cm = 0.1 m

g (gravity ) = 9.8 m/s^2

p = 20 x 0.1 x 9.8 = 19.6 atm